1/s+1/s`=1/f
the focal point of the lens is the point where the parallel beam refract to. after the beams hits the surface
we measured f equals 14.97cm
by using a double convex mirror we can increase distance between the object and mirror by a factor of the focal length, to produce different images smaller and larger depending on how far the object is from the double convex mirror.
d_0 cm | d_i cm | h_i cm | h_0 cm | |
79.88 | 23.45 | 1.3 | 3 | |
59.88 | 24.5 | 1.75 | 3 | |
39.98 | 28.7 | 1.95 | 3 | |
29.99 | 44.5 | 5.2 | 3 | |
22.96 | 332.5 | 53.6 | 3 | |
if we change the object distance to about .5 the focal length the image would become to large for us to see, so we would assume that as the lens become closer to the object the image we receive is going to get larger.
if we look through the lens at the object and view the image when the focal length .5, we the the image upright and big.
analysis
from the experiment we observed that the image is always inverted, along both the vertical and horizontal axis, if this was a single convex mirror then the image would not have have been inverted.
the two lens are going to have a different length in R, if we take that in to considerations we get
1/R1+1/R2=1/s+1/s`
the slope of the negative inverse d_0 to the negative inverse d_i is about .565 this would be the degree M that the image is changing. like we observed if the object was getting further away then the image would become smaller and smaller till it becomes to small to measure.
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