when we stand in front of a convex mirror, the image appears to be smaller than the object itself, it does however stays upright, and is located about the same position inside and outside the mirror.
when the object is moved closer to the mirror the image becomes bigger, and when it is moved further away the image gets smaller.
for the convex mirror we gotten the object height to be around 3.1cm+_.034cm
the distance of the object about 6.2cm+_.45cm
the image height about .7cm+_.23cm
and the image distance to be 2.3cm+_.31cm
we are given an equation for M which equals h_i/h_0 which gets you M = 0.2258
there is no units for M it is just a scalar number
PartII
now we can look at concave mirrors, the image that appears in the mirror is larger, but it is inverted, and relative to the position of the mirror the object well seem closer.
moving the object closer to the mirror makes the image smaller, and upright and as for moving further away the image grows to infinite
for the concave mirror we gotten the object height to be around 3.1cm+_.034cm
the distance of the object about 6.2cm+_.45cm
the image height about 1.7cm+_.23cm
and the image distance to be 2.3cm+_.31cm
again we get M to be about .463+_.012 (no units)
my sketch is a little off on the height of the image, but that could have been me measuring it wrong, but the difference wouldn't matter.
analysis
in this experiment we can clearly see how convex and concave mirrors would work on an object being placed in front of them, we also identified how we can see the image in the mirror by drawing lines to where the focal point, the lens of the mirror and the center of the sphere. knowing that we can find the height of the image, with the magnification of the object.
m= - s`/s
from this we can find m then we can use m to find y
m= y`/y
m= - s`/s
from this we can find m then we can use m to find y
m= y`/y
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